The distance-time graph of a particle at time $t$ makes angle 45${^\circ}$ with time axis. After 1s, it makes angle 60${^\circ}$ with time axis. What is the acceleration of the particle? [image:3_image50.emf]

Question

Dr. Abubacker · Accepted Answer

(a) The slope of distance-time graphs speed.
The change in velocity in 1 s
$= 	an{60{^\circ}} - 	an{45{^\circ}} = \sqrt{3} -$1
$	herefore$ Acceleration $= \frac{\mathrm{\Delta}v}{\mathrm{\Delta}t} = \frac{\sqrt{3} - 1}{1} = (\sqrt{3} - 1)$unit

Q. The distance-time graph of a particle at time $t$ makes angle 45${^\circ}$ with time axis. After 1s, it makes angle 60${^\circ}$ with time axis. What is the acceleration of the particle?

Explanation

Reviewed by Dr. Abubacker

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