Q. A particle covers 4m, 5m, 6m, and 7m, in 3rd, 4th, 5th and 6th second respectively. The particle starts
A) With an initial non-zero velocity and moves with uniform acceleration
B) From rest and moves with uniform velocity
C) With an initial velocity and moves with uniform velocity
D) From rest and moves with uniform acceleration
Explanation
(a) $4 = u + \frac{a}{2}(2 \times 3 - 1)$or $4 = u + \frac{5a}{2},$
$5 = u + \frac{a}{2}(2 \times 4 - 1)$ or $5 = u + \frac{7a}{2}$
Subtracting, $1 = \frac{7a}{2} - \frac{5a}{2} = \frac{2a}{2} = a$
Again, $4 = u + \frac{5}{2}$ or $u = 4 - \frac{5}{2} = 1.5ms^{- 1}$
So, the initial velocity is non-zero and acceleration is uniform.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.