Q. Velocity-time $(v$-$t)$ graph for a moving object is shown in the figure. Total displacement of the object during the same interval when there is non-zero acceleration and retardation is
A) $60\ m$
B) $50\ m$
C) $30\ m$
D) $40\ m$
Explanation
(b) Between time interval $20\ sec$ to $40\ sec$, there is non-zero acceleration and retardation. Hence distance travelled during this interval
$=$ Area between time interval $20\ sec$ to $40\ sec$
$= \frac{1}{2} \times 20 \times 3 + 20 \times 1 = 30 + 20 = 50\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.