Q. The velocity-time graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in $6\ sec$ are respectively
A) $8\ m,\ 16\ m$
B) $16\ m,\ 8\ m$
C) $16\ m,\ 16\ m$
D) $8\ m,\ 8\ m$
Explanation
(a) Displacement = Summation of all the area with sign
$= \left( A_{1} \right) + \left( - A_{2} \right) + \left( A_{3} \right) = (2 \times 4) + ( - 2 \times 2) + (2 \times 2)$
[image:3_image173.emf]
$\therefore Displacement = 8\ m$
Distance = Summation of all the areas without sign
$= \left| A_{1} \right| + \left| - A_{2} \right| + \left| A_{3}\ \right| = |8| + | - 4| + |4| = 8 + 4 + 4$
$\therefore Distance = 16\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.