Q. A body released from a great height falls freely towards the earth. Another body is released from the same height exactly one second later. The separation between the two bodies two second after the release of the second body is
A) 9.8 m
B) 4.9 m
C) 24.5 m
D) 19.6 m
Explanation
(c) $\mathrm{\Delta}x = \frac{1}{2}gt^{2} - \frac{1}{2}g(t - 1)^{2}$
$= \frac{1}{2}g\left\lbrack t^{2} - (t - 1)^{2} \right\rbrack = \frac{1}{2}g(2t - 1)$
$= \frac{1}{2} \times 9.8 \times 5$m=24.5m
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.