Q. The particles $A,\ B$ and $C$ are thrown from the top of a tower with the same speed. $A$ is thrown up, $B$ is thrown down and $C$ is horizontally. They hit the ground with speeds $V_{A},\ V_{B}$ and $V_{C}$ respectively
A) $V_{A} = V_{B} = V_{C}$
B) $V_{A} = V_{B} > V_{C}$
C) $V_{B} > V_{C} > V_{A}$
D) $V_{A} > V_{B} = V_{C}$
Explanation
The correct answer is Option A: $V_{A} = V_{B} = V_{C}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.