Q. A body freely falling from the rest has a velocity $'v'$ after it falls through a height ‘$h'$. The distance it has to fall down for its velocity to become double, is
A) $2h$
B) $4h$
C) $6h$
D) $8h$
Explanation
(b) Let at point $A$ initial velocity of body is equal to zero
for path $AB:v^{2} = 0 + 2gh\ \ \ \ldots(i)$
for path $AC:(2v)^{2} = 0 + 2gx$
$4v^{2} = 2gx$ …(ii)
Solving (i) and (ii),$\ x = 4h$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.