(c) Taking the starting point as $O,$ we have 30 m north $OA,$ 20 m east $AB,$ and finally $30\sqrt{2}\ m(S - W)BD.$
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From $\mathrm{\Delta}\ CAB,$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ AC = 20\ m,\ OC = 10\ m$
In $\mathrm{\Delta}\ OCD,$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ OD = OC,\ OD = 10\ m$
Hence, final displacement from origin is 10 m.