Q. A body of $mass$ 10 $kg\ $is moving with a constant velocity of $10\ m/s$.When a constant force acts for 4 $seconds$ on it, it moves with a velocity 2 $m/sec$ in the opposite direction. The acceleration produced in it is
A) $3m/\sec^{2}\ $
B) $- 3m/\sec^{2}\ $
C) $0.3m/\sec^{2}\ $
D) $- 0.3m/\sec^{2}\ $
Explanation
(b) $v = u + at\ \Rightarrow \ - 2 = 10 + a \times 4\ \Rightarrow a = - 3m/\sec^{2}\ $
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.