A point particle starting from rest has a velocity that increase linearly with time such that $v = pt,$ where $p = 4ms^{- 2}$. The distance covered in the first 2 $s$ will be

Question

Dr. Abubacker · Accepted Answer

(c) Given, $v = pt$
$\int_{0}^{X}{dx = p\int_{0}^{2}{t\ dt}}$
$= \frac{pt^{2}}{2} = \frac{4 	imes 4}{2} = 8$m

Q. A point particle starting from rest has a velocity that increase linearly with time such that $v = pt,$ where $p = 4ms^{- 2}$. The distance covered in the first 2 $s$ will be

Explanation

Reviewed by Dr. Abubacker

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