Q. A cricket ball is thrown up with a speed of $19.6\ ms^{- 1}$. The maximum height it can reach is
A) $9.8\ m$
B) $19.6\ m$
C) $29.4\ m$
D) $39.2\ m$
Explanation
(b) $H_{\max} = \frac{u^{2}}{2g} = \frac{19.6 \times 19.6}{2 \times 9.8} = 19.6\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.