The velocity-time relation of an electron starting from rest is given by $v = kt$ where $k = 2ms^{- 1}$. The distance traversed in first 3 s is

Question

Dr. Abubacker · Accepted Answer

(a) Given that $u = 0$ (the electron starts from rest), At any time $v = kt = 2t$
$a = \frac{du}{dt} = 2ms^{- 1}$(Constant acceleration)
Now $s = ut + \frac{1}{2}at^{2}$
$= 0 	imes 3 + \frac{1}{2} 	imes 2 	imes (3)^{2}$
$= 9$m

Q. The velocity-time relation of an electron starting from rest is given by $v = kt$ where $k = 2ms^{- 1}$. The distance traversed in first 3 s is

Explanation

Reviewed by Dr. Abubacker

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