Q. A ball is dropped downwards. After 1 second another ball is dropped downwards from the same point. What is the distance between them after 3 seconds
A) $25\ m$
B) $20\ m$
C) $50\ m$
D) $9.8\ m$
Explanation
(a) Distance between the balls = Distance travelled by first ball in 3 seconds – Distance travelled by second ball in 2 seconds = $\frac{1}{2}g(3)^{2} - \frac{1}{2}g(2)^{2} = 45 - 20 = 25\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.