Q. A tiger chases a deer 30m ahead of it and gains 3m in 5s after the chase began. The distance gained by the tiger in 10 s is
A) 6m
B) 12 m
C) 18 m
D) 20 m
Explanation
(b) If $a$ in the relative acceleration, then
$3 = \frac{1}{2}a \times 5 \times 5$ or $a = \frac{6}{25}ms^{- 2}$
Again, $S = \frac{1}{2} \times \frac{6}{25} \times 10 \times 10 = 12$m
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.