Q. An object dropped from rest. Its $\ v - t$ graph is
A) [image:3_image69.emf]
B) [image:3_image70.emf]
C) [image:3_image71.emf]
D) [image:3_image72.emf]
Explanation
(a) From first equation of motion
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v = u + at$
As object starts from rest, so $u = 0$
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v = at\ or\ v \propto t$
Therefore, $v - t$ graph is a straight line passing through $O.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.