(d) Let acceleration is $a$ and retardation is $- 2a.$ Then for accelerating motion
$\ \ t_{1} = \frac{v}{a}$ ….(i)
For retarding motion, $t_{2} = \frac{v}{2a}$ ….(ii)
Given,
$t_{1} + t_{2} = 9\ \Rightarrow \frac{v}{a} + \frac{v}{2a} = 9\ \Rightarrow \frac{3v}{2a} = 9\ \Rightarrow \frac{v}{a} = 6$
Hence, duration of acceleration, $t_{1} = 6\ s$