Q. A body moves for a total of nine second started from rest with uniform acceleration and then with uniform retardation, which is twice the value of acceleration and then stops. The duration of uniform acceleration

A) 3 s
B) 4.5 s
C) 5 s
D) 6 s
Explanation

(d) Let acceleration is $a$ and retardation is $- 2a.$ Then for accelerating motion
$\ \ t_{1} = \frac{v}{a}$ ….(i)
For retarding motion, $t_{2} = \frac{v}{2a}$ ….(ii)
Given,
$t_{1} + t_{2} = 9\ \Rightarrow \frac{v}{a} + \frac{v}{2a} = 9\ \Rightarrow \frac{3v}{2a} = 9\ \Rightarrow \frac{v}{a} = 6$
Hence, duration of acceleration, $t_{1} = 6\ s$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.