A very large number of balls are thrown vertically upwards in quick succession in such a way that the next ball is thrown when the previous one is at the maximum height. If the maximum height is $5m$, the number of ball thrown per minute is (take $g = 10\ ms^{- 2}$)

Question

Dr. Abubacker · Accepted Answer

(c) Maximum height of ball $= 5\ m$
So velocity of projection $\Rightarrow u = \sqrt{2gh} = 10\ m/s$
Time interval between two balls (time of ascent)
$= \frac{u}{g} = 1\ sec = \frac{1}{60}\ min$
So number of ball thrown per min $= 60$

Q. A very large number of balls are thrown vertically upwards in quick succession in such a way that the next ball is thrown when the previous one is at the maximum height. If the maximum height is $5m$, the number of ball thrown per minute is (take $g = 10\ ms^{- 2}$)

Explanation

Reviewed by Dr. Abubacker

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