Q. A particle moving with a uniform acceleration along a straight line covers distance $a$ and $b$ in successive intervals of $p$ and $q$ second. The acceleration of the particle is
A) $\frac{pq(p + q)}{2(bp - aq)}$
B) $\frac{2(aq - bp)}{pq(p - q)}$
C) $\frac{bp - aq}{pq(p - q)}$
D) $\frac{2(bp - aq)}{pq(p - q)}$
Explanation
(b) According to problem, when
$s = a,t = p$
$\because\ s = ut + \frac{1}{2}ft^{2}$ (here, $f =$acceleration)
$\therefore\ a = up + \frac{fp^{2}}{2}$ (i)
For $s = b,t = q$
$b = uq + \frac{fq^{2}}{2}$ (ii)
After solving Eqs. (i) and (ii),
$f = \frac{2(aq - bp)}{pq(p - q)}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.