Q. The graph between the displacement $x$ and $t$ for a particle moving in a straight line is shown in figure. During the interval $OA,AB,BC$ and $CD,$ the acceleration of the particle is $OA,\ AB,\ BC$, $CD$
A) + 0 + +
B) - 0 + 0
C) + 0 - +
D) - 0 - 0
Explanation
(b) Region $OA$ shows that graph bending toward time axis $i.e.$ acceleration is negative.
Region $AB$ shows that graph is parallel to time axis $i.e.\ $velocity is zero. Hence acceleration is zero.
Region $BC$ shows that graph is bending towards displacement axis $i.e.$ acceleration is positive.
Region $CD\ $shows that graph having constant slope $i.e.$ velocity is constant. Hence acceleration is zero
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.