(c) Stopping distance$= \frac{Kinetic\ energy\ }{Retarding\ force} = \frac{\frac{1}{2}mu^{2}}{F}$ $= \frac{u^{2}}{2\mu g}\lbrack F = \mu mg\rbrack$ So both will cover equal distance
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.