Q.
A particle moves along the sides $AB,BC,CD$ of a square of side $25\ m$ wuth a velocity of $15\ ms^{- 1}$. Its average velocity is
A) $15\ ms^{- 1}$
B) $10ms^{- 1}$
C) $7.5ms^{- 1}$
D) $5ms^{- 1}$
Explanation
(d) Average velocity =$\frac{Total\ Displacement\ }{Time\ taken\ } = \frac{25}{75/15} = 5m/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.