The $x$ and $y$ coordinates of a particles at any time $t$ are given by $x = 7t + 4t^{2}$ and $y = 5t,$ where $x$ and $y$ are in metre and $t$ in second. The acceleration of particle at $t = 5s$ is

Question

Dr. Abubacker · Accepted Answer

(b) $a = \sqrt{a_{x}^{2} + a_{y}^{2}}$
$= \left\lbrack \left( \frac{d^{2}x}{dy} \right)^{2} + \left( \frac{d^{2}y}{dt^{2}} \right)^{2} \right\rbrack^{\frac{1}{2}}$
Here, $\frac{d^{2}y}{dx^{2}} = 0$
Hence, $a = \frac{d^{2}x}{dt^{2}} = 8ms^{- 2}$

Q. The $x$ and $y$ coordinates of a particles at any time $t$ are given by $x = 7t + 4t^{2}$ and $y = 5t,$ where $x$ and $y$ are in metre and $t$ in second. The acceleration of particle at $t = 5s$ is

Explanation

Reviewed by Dr. Abubacker

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