Two stones of equal masses are dropped from a rooftop of height $h$ one after another. Their separation distance against time will

Question

Dr. Abubacker · Accepted Answer

(b) $h = \frac{1}{2}gt^{2}$
$h^{'} = \frac{1}{2}g\left( t - t_{0} \right)^{2}$
$h - h^{'} = \frac{1}{2}g\lbrack t^{2} - \left( t - t_{0} \right)^{2}\rbrack$
$= \frac{1}{2}g\left\lbrack t^{2} - t^{2} - t_{0}^{2} + 2tt_{0} \right\rbrack$
$\mathrm{\Delta}h = \frac{1}{2}gt_{0}\left( 2t - t_{0} \right)$
$\mathrm{\Delta}h$ is increasing with time

Q. Two stones of equal masses are dropped from a rooftop of height $h$ one after another. Their separation distance against time will

Explanation

Reviewed by Dr. Abubacker

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