Q. A small block sides without friction down an inclined plane starting from rest. Let $S_{n}$ be the distance travelled from time $t = n - 1$ to $t = n$. Then $\frac{S_{n}}{S_{n + 1}}$ is
A) $\frac{2n - 1}{2n}$
B) $\frac{2n + 1}{2n - 1}$
C) $\frac{2n - 1}{2n + 1}$
D) $\frac{2n}{2n + 1}$
Explanation
(c) $S_{n} = \frac{1}{2}g\cos\theta(2n - 1),\ S_{n + 1} = \frac{1}{2}g\cos\theta\left\{ 2(n + 1) - 1 \right\}$
$\frac{S_{n}}{S_{n + 1}} = \frac{2n - 1}{2n + 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.