Q.
Acceleration velocity graph of a particle moving in a straight line is as shown in figure. The slope of velocity-displacement graph
A) Increases linearly
B) Decreases linearly
C) Is constant
D) Increases parabolically
Explanation
(c) From acceleration-velocity graph, we have $a = k\ v\ $where $k$ is a constant which represents the slope of the given line.
As, $a = v\frac{dv}{ds},$ so $v = \frac{dv}{ds} = kv$
or $\frac{dv}{ds} = k = a$ constant
Thus, the slope of velocity-displacement graphs is same as that of acceleration velocity. Which is constant.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.