Q. A particle starts from rest at $t = 0$ and undergoes an acceleration $a$ in ${ms}^{- 2}$ with time $t$ in second which is as shown Which one of the following plot represents velocity $v$ in ${ms}^{- 1}\ versus$ time $t$ in second?

A)
B)
C)
D)
Explanation

(a) A particle starts from rest at $t = 0$
The equation of motion
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v = u + at = 0 + 3 \times 2 = 6\ {ms}^{- 1}$
The velocity for next 2 s
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v^{''''''''} = v + at$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 6 - 3 \times 2 = 0$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v^{''''''''} = 0$
[image:3_image192.emf]
Hence, $v - t$ graph will be as shown.
[image:3_image193.emf]

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.