(a) A particle starts from rest at $t = 0$
The equation of motion
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v = u + at = 0 + 3 \times 2 = 6\ {ms}^{- 1}$
The velocity for next 2 s
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v^{''''''''} = v + at$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 6 - 3 \times 2 = 0$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v^{''''''''} = 0$
[image:3_image192.emf]
Hence, $v - t$ graph will be as shown.
[image:3_image193.emf]