Q. The velocity of a particle is $v = v_{0} + gt + ft^{2}$. If its position is $x = 0$ at $t = 0$, then its displacement after unit time $(t = 1)is$
A) $v_{0} = 2g + 3f$
B) $v_{0} + g/2\ + f/3$
C) $v_{0} + g + f$
D) $v_{0} + g/2 + f$
Explanation
(b) $\int_{0}^{x}{dx} = \int_{0}^{1}{(v_{0} + gt + ft^{2})dt}$
$x = v_{0} + g\left( \frac{1}{2} \right) + f\left( \frac{1}{3} \right)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.