Q. A body freely falling from rest has a velocity $v$ after it falls through distance $h$. The distance it has to fall down further for its velocity to become double is
A) $h$
B) 2$h$
C) 3$h$
D) 4$h$
Explanation
(c) $(2v)^{2} - v^{2} = 2gh'$ or $4v^{2} - v^{2} = 2gh'$
or $\ 3v^{2} = 2gh'$ or $3 \times 2gh = 2gh'$ or $h^{'} = 3h$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.