Q. Two bodies of different masses are dropped from heights of 16 m and 25 m respectively. The ratio of the time taken by them to reach the ground is
A) $\frac{25}{16}$
B) $\frac{5}{4}$
C) $\frac{4}{5}$
D) $\frac{16}{25}$
Explanation
(c) $h = 0 + \frac{1}{2}gt^{2}\ \Rightarrow t^{2} \propto h$
$\therefore\frac{t_{1}}{t_{2}} = \sqrt{\frac{h_{1}}{h_{2}}} = \sqrt{\frac{16}{25}} = \frac{4}{5}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.