Q. A particle starts from rest. Its acceleration $(a)$ versus time $(t)$ is as shown in the figure. The maximum speed of the particle will be
A) $110\ m/s$
B) $55\ m/s$
C) $550\ m/s$
D) $660\ m/s$
Explanation
(b) The area under acceleration time graph gives change in velocity. As acceleration is zero at the end of $11\ sec$
i.e. $v_{\max} =$Area of$\ \mathrm{\Delta}OAB$
$= \frac{1}{2} \times 11 \times 10 = 55\ m/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.