Q. A particle moving in a straight line covers half the distance with speed of $3\ m/s$. The other half of the distance is covered in two equal time intervals with speed of $4.5\ m/s$ and $7.5\ m/s$ respectively. The average speed of the particle during the motion is

A) $4.0\ m/s$
B) $5.0\ m/s$
C) $5.5\ m/s$
D) $4.8\ m/s$
Explanation

(a) If $t_{1}$ and $2t_{2}$ are the time taken by particle to cover first and second half distance respectively
$t_{1} = \frac{x/2}{3} = \frac{x}{6}$ …(i)
$x_{1} = 4.5\ t_{2}$ and $x_{2} = 7.5\ t_{2}$
So, $x_{1} + x_{2} = \frac{x}{2} \Rightarrow 4.5\ t_{2} + 7.5\ t_{2} = \frac{x}{2}$
$t_{2} = \frac{x}{24}$ …(ii)
Total time $t = t_{1} + 2t_{2} = \frac{x}{6} + \frac{x}{12} = \frac{x}{4}$
So, average speed $= 4\ m/sec$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.