A ball is dropped vertically downwards from a height $d$ above the ground. It hits the ground and bounces up vertically to a height $d/2$. Neglecting subsequent motion and air resistance, its speed varies with the height $h$ above the ground as

Question

Dr. Abubacker · Accepted Answer

(b) For downward motion.
$v^{2} = u^{2} + 2gh$
For upward motion,
$v^{2} = u^{2} - 2gh$
The graph will be parabolic in both case. But velocities will be opposite. But speed never be negative.
Hence, (b) is correct.

Q. A ball is dropped vertically downwards from a height $d$ above the ground. It hits the ground and bounces up vertically to a height $d/2$. Neglecting subsequent motion and air resistance, its speed varies with the height $h$ above the ground as

Explanation

Reviewed by Dr. Abubacker

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