
(b) Let $v$ be the speed of boatman is still water.
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Resultant of $v$ and $u$ should be along $AB$. Components of ${\overrightarrow{v}}_{b}$ (absolute velocity of boatman)along $x$ and $y$ direction are,
$v_{x} = u - v\ $sin$\theta$
Further, $\tan{45{^\circ}} = \frac{v_{y}}{v_{X}}$
or 1=$\frac{v\ cos\theta}{u - v\ sin\theta}$
$v = \frac{u}{\sin\theta + \cos\theta} = \frac{u}{\sqrt{2}sin(\theta + 45{^\circ})}$
$v$ is minimum at,
$\theta + 45{^\circ} = 90{^\circ}$ or $\theta = 45{^\circ}$
and $v_{\min} = \frac{u}{\sqrt{2}}$