Q. The position of a particle moving along x-axis at certain times is given below: [table] $t(s)$ | 0 | 1 | 2 | 3 ; $x(m)$ | -2 | 0 | 6 | 16 [/table] Which of the following describes the motion correctly
A) Uniform accelerated
B) Uniform decelerated
C) Non-uniform accelerated
D) There is not enough data for generalization
Explanation
(c) $Instantaeneous\ velocity = v = \frac{\mathrm{\Delta}x}{\mathrm{\Delta}t}$
By using the data from the table
$v_{1} = \frac{0 - ( - 2)}{1} = 2m/s,\ \ \ \ v_{2} = \frac{6 - 0}{1} = 6m/s$
$v_{3} = \frac{16 - 6}{1} = 10m/s$
So, motion is non-uniform but accelerated
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.