Q. The displacement of a particle is proportional to the cube of time elapsed. How does the acceleration of the particle depends on time obtained
A) $a \propto t^{2}$
B) $a \propto 2t$
C) a$\propto t^{3}$
D) $a \propto t$
Explanation
(d) $x \propto t^{3}\therefore x = {Kt}^{3}$
$\Rightarrow v = \frac{dx}{dt} = 3Kt^{2}\ and\ a = \frac{dv}{dt} = 6Kt$
$i.e.a \propto t$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.