(d) $A \Rightarrow \frac{u^{2}}{4} - u^{2} = - 2gh_{1}$
$B \Rightarrow \frac{u^{2}}{9} - u^{2} = - 2gh_{2}$
$C \Rightarrow \frac{u^{2}}{16} - u^{2} = - 2gh_{3}$
[image:3_image201.emf]
$\therefore AB = \frac{u^{2}}{2g}\left\{ \frac{8}{9} - \frac{3}{4} \right\} = \frac{u^{2}}{2g}.\frac{5}{36}$
$BC = \frac{u^{2}}{2g}\left\{ \frac{15}{16} - \frac{8}{9} \right\} = \frac{u^{2}}{2g}.\frac{7}{144}$
$\therefore\frac{AB}{BC} = \frac{5}{36} \times \frac{144}{7} = \frac{20}{7}$