Q. A body is thrown vertically up with a velocity $u$. It passes three points $A,B$ and $C$ in its upward journey with velocities $\frac{u}{2},\frac{u}{3}$ and $\frac{u}{4}$ respectively. The ratio of the separations between points $A$ and $B$ and between $B$ and $C\ i.e.,\frac{AB}{BC}$ is

A) 1
B) 2
C) $\frac{10}{7}$
D) $\frac{20}{7}$
Explanation

(d) $A \Rightarrow \frac{u^{2}}{4} - u^{2} = - 2gh_{1}$
$B \Rightarrow \frac{u^{2}}{9} - u^{2} = - 2gh_{2}$
$C \Rightarrow \frac{u^{2}}{16} - u^{2} = - 2gh_{3}$
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$\therefore AB = \frac{u^{2}}{2g}\left\{ \frac{8}{9} - \frac{3}{4} \right\} = \frac{u^{2}}{2g}.\frac{5}{36}$
$BC = \frac{u^{2}}{2g}\left\{ \frac{15}{16} - \frac{8}{9} \right\} = \frac{u^{2}}{2g}.\frac{7}{144}$
$\therefore\frac{AB}{BC} = \frac{5}{36} \times \frac{144}{7} = \frac{20}{7}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.