Q. The position of a particle $x$ (in metres) at a time $t$ seconds is given by the relation $\overrightarrow{r} = (3t\widehat{i} - t^{2}\widehat{j} + 4\widehat{k})$. Calculate the magnitude of velocity of the particle after 5 seconds

A) $3.55$
B) $5.03$
C) $8.75$
D) $10.44$
Explanation

(d) $\overrightarrow{r} = 3t\widehat{i} - t^{2}\widehat{j} + 4\widehat{k}$
Velocity, $\overrightarrow{v} = \frac{d\overrightarrow{r}}{dt} = \frac{d}{dt}\left( 3t\widehat{i} - t^{2}\widehat{j} + 4\widehat{k} \right) = 3\widehat{i} - 2t\widehat{j}$
At $t = 5s \Rightarrow \overrightarrow{v} = 3\widehat{i} - 10\widehat{j}$
$\left| \overrightarrow{v} \right| = \sqrt{(3)^{2} + ( - 10)^{2}} = \sqrt{9 + 100} = \sqrt{109} = 10.44\ ms^{- 1}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.