Q. A particle moves along with $x -$axis. The position x of particle with respect to time $t$ from origin given by $x = b_{0} + b_{1}t + b_{2}t^{2}.$ The acceleration of particle is
A) $b_{0}$
B) $b_{1}$
C) $b_{2}$
D) $2b_{2}$
Explanation
(d) Distance, $x = b_{0} + b_{1}t + b_{2}t^{2}$
Velocity $v = \left( \frac{dx}{dt} \right) = b_{1} + 2b_{2}t$
Acceleration, $\ \ \ \ \ a = \frac{d^{2}x}{dt^{2}} = 2b_{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.