Q.
A particle starts from rest. Its acceleration $(a)\ versus$ time $(t)$ is as shown in the figure. The maximum speed of the particle will be
A) $110\ {ms}^{- 1}$
B) $55\ {ms}^{- 1}$
C) $550\ {ms}^{- 1}$
D) $660\ {ms}^{- 1}$
Explanation
(b) Area under acceleration-time graph gives the change in velocity. Hence,
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v_{\max} = \frac{1}{2} \times 10 \times 11 = 55\ {ms}^{- 1}$
Therefore, the correct option is (b).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.