Q.
Figure shows the graphical variation of displacement with time for the case of a particle moving along a straight line. The accelerations of the particle during the intervals $OA,AB,BC$ and $CD$ are respectively
A) $OA$ $AB$ $BC$ $CD$
B) $-$ 0 + 0
C) + 0 + +
D) $-$ 0 $-$ 0
Explanation
(a) The portion $OA$ of the graphs is convex upward. It represents negative acceleration. The portion $AB$ represents negative acceleration. The portion $AB$ represents that $x$ is not changing with time. Clearly, it is a case of zero acceleration. The portion $BC$ of the graph is concave upward. It represents positive acceleration. The portion $CD$ is a straight line sloping upward to the right. It represents uniform velocity and hence acceleration is zero
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.