(c) $\therefore\ x = a$cos $\omega t$
$\therefore v = \frac{dx}{dt} = - a\omega\sin{\omega t}$
The instantaneous speed is given by modulus of instantaneous velocity.
$\therefore\ \ \ $speed$= |u| = \left| - a\omega\sin{\omega t} \right|$
Hence, (c) is correct.