Q. An automobile in travelling at $50\ {kmh}^{- 1},$ can be stopped at a distance of 40 m by applying brakes. If the same automobile is travelling at $90\ {kmh}^{- 1},\ $ all other conditions remaining same and assuming no skidding, the minimum stopping distance in metre is

A) 72
B) 92.5
C) 102.6
D) 129.6
Explanation

(d) Stopping distance $s \propto u^{2}$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{s_{2}}{40} = \left( \frac{90 \times \frac{5}{18}}{50 \times \frac{5}{18}} \right)^{2}$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ s_{2} = 129.6\ m$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.