(a) Here, $t_{1} = \frac{x}{v} + \frac{x}{v} = \frac{2x}{v},t_{2} = \frac{x}{v + \omega} = \frac{x}{v - \omega} + \frac{2xv}{v^{2} - \omega^{2}}$
or $t_{2} = \frac{2xv}{v^{2}\left( 1 - \frac{\omega^{2}}{v^{2}} \right)} = \frac{2x}{v^{\ }\left( 1 - \frac{\omega^{2}}{v^{2}} \right)}$
or $t_{2} = \frac{t_{1}}{1 - \frac{\omega^{2}}{v^{2}}}$
or $t_{2} > t_{1}$