A particle moves along a straight line such that its displacement at any time $t$ is given by $S = t^{3} - 6t^{2} + 3t + 4\ metres$ The velocity when the acceleration is zero is

Question

Dr. Abubacker · Accepted Answer

(d) $v = \frac{ds}{dt} = 3t^{2} - 12t + 3$ and $a = \frac{dv}{dt} = 6t - 12$
For $a = 0$, we have $t = 2$ and at $t = 2,\ v = - 9\ ms^{- 1}$

Q. A particle moves along a straight line such that its displacement at any time $t$ is given by $S = t^{3} - 6t^{2} + 3t + 4\ metres$ The velocity when the acceleration is zero is

Explanation

Reviewed by Dr. Abubacker

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