Q. Two balls $A$ and $B$ are thrown simultaneously from the top of a tower. $A$ is thrown vertically up with a speed of 4$ms^{- 1}$. $B$ is thrown vertically down with a speed of $4\ ms^{- 1}$. The ball $A$ and $B$ hit the ground with speed $v_{A}$ and $v_{B}$ respectively. Then,
A) $v_{A} < v_{B}$
B) $v_{A} > v_{B}$
C) $v_{A}\underline{\gtrless}v_{B}$
D) $v_{A} = v_{B}$
Explanation
(d) When $A$ returns to the ‘level’ of top of tower, its downward velocity is 4$ms^{- 1}$. This velocity is the same a that of $B$. So, both $A$ and $B$ hit the ground with the same velocity.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.