Q. The variation of velocity of a particle with time moving along a straight line is illustrated in the following figure. The distance travelled by the particle in four seconds is

A) $60\ m$
B) $55\ m$
C) $25\ m$
D) $30\ m$
Explanation

(b) Distance = Area under $v - t$ graph =$A_{1} + A_{2} + A_{3} + A_{4}$
$= \frac{1}{2} \times 1 \times 20 + (20 \times 1) + \frac{1}{2}(20 + 10) \times 1 + (10 \times 1)$
$= 10 + 20 + 15 + 10 = 55m$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.