(a) Here, $u = 10\ ms^{- 1},\ t = 2s,\ S = 20\ m$ Using $S = ut + \frac{1}{2}at^{2}$ $\therefore\ 20 = 10 \times 2 + \frac{1}{2} \times a \times 2^{2}$ $0 = 2a \Rightarrow a = 0$
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