Q. A particle moving with a uniform acceleration travels 24 $m$ and 64 $m\ $in the first two consecutive intervals of 4 $\sec$ each. Its initial velocity is
A) $1\ m/sec$
B) 10$\ m/sec$
C) 5$\ m/sec$
D) 2$\ m/sec$
Explanation
(a) Distance travelled in 4 sec
$24 = 4u + \frac{1}{2}\alpha \times 16\ \ \ \ \ldots(i)$
Distance travelled in 8 sec
$88 = 8u + \frac{1}{2}\alpha \times 64\ \ \ \ \ldots(ii)$
After solving (i) and (ii), we get $u = 1m/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.