A particle moves along $X$- axis in such a way that its coordinate $X$ varies with time $t$ according to the equation $x = (2 - 5t + 6t^{2})m$. The initial velocity of the particle is

Question

Dr. Abubacker · Accepted Answer

(a) The velocity of the particle is
$\frac{dx}{dt} = \frac{d}{dt}\left( 2 - 5t + 6t^{2} \right) = (0 - 5 + 12t)$
For initial velocity $t = 0$, hence $v = - 5\ m/s$

Q. A particle moves along $X$- axis in such a way that its coordinate $X$ varies with time $t$ according to the equation $x = (2 - 5t + 6t^{2})m$. The initial velocity of the particle is

Explanation

Reviewed by Dr. Abubacker

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