Q. Acceleration of a body when displacement equation is $3s = 9t + 5t^{2}$ is
A) 5/3
B) 14/3
C) 10/3
D) 19/3
Explanation
(c) Given, $3s = 9t + 5t^{2}or\ s = \frac{1}{3}\left( 9t + 5t^{2} \right)$
Velocity $v = \frac{ds}{dt} = \frac{1}{3}(9 + 10t)$
Acceleration $a = \frac{d}{dt}\left( \frac{ds}{dt} \right) = \frac{d^{2}s}{dt^{2}} = \frac{10}{3}\ units.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.